Question

if one root of the quadratic equation 2x²+kx+4=0 is 2 then the value of k is

Answer 1

Answer:

k=-6

Step-by-step explanation:

Let p(x)=2x²+kx+4=0 then,

If we substitute the value 2 in the eqn. p(x)

we know p(2) = 0

so, 2*(2)^2+k*(2)+4 = 0

8+2k+4 = 0

12+2k = 0

2k = -12

k = -6