Math, asked by s10b1555sajid02039, 4 months ago

If one root of the quadratic equation 2y²+py-6=0 is 2, the value of p is

Answers

Answered by shobhasaini160

0

Step-by-step explanation:

2y²+py-6=0

put p=2

2×2²+p×2-6=0

8+2p-6=0

2+2p=0

p= -1

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