Question

If one root of the quadratic equation
3 x²+ px+4 =0 is 2√3, then find the value of
the other root of the equation.​

Answer 1

Answer:

2/3√3

Step-by-step explanation:

product of roots = 4/3

Let the other root be x

x × 2√3 = 4/3

x = 2/3√3

Answer 2

Answer:

2/(3√3), p = -20/(√3)

Step-by-step explanation:

let the other root be "x"

product of both the roots=c/a

x*2√3 = 4/3

x = 2/(3√3)

Also, sum of both roots = -b/a

2/(3√3) + 2√3 = -p/3

[2 + (2√3)(3√3)]/3√3 = -p/3

(2 + 18)/√3 = -p

p = -20/√3