Question

if one root of the quadratic equation 3y²-ky+8=0 is ⅔ find the value of k ​

Answer 1

Answer:

14

Step-by-step explanation:

We know that product of roots is c/a.

Another root = 8/3*3/2

=4

-k/3=-(sum of roots)

k/3=(4+2/3)

k/3=(14/3)

k=14

Answer 2

Answer:

Step-by-step explanation:

As 2/3 is the zero of the given equation.

Put, y=2/3 in the eq.

3(2/3)² - k(2/3) + 8 = 0

3(4/9) - 2k/3 + 8 = 0

4/3 - 2k/3 + 24/3 =0

4 - 2k + 24 = 0

-2k = -28

k = -28/-2  = 14

Hence, the other zero of the polynomial is 14.