if one root of the quadratic equation 4x square-px+5=0 is -3 find the value of p also find the other root
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4x²-PX+5=0
4(-3)²+3p+5=0
4(9)+3p+5=0
36+5=-3p
41÷-3=p
p= -13.67
first root alpha= -3
so second root = bita
given equation=
4x²+41/3x+5=0 (including value of p)
comparing with ax²+bx+c=o
a=4,b=41/3,c=5
sum of roots=
4(-3)²+3p+5=0
4(9)+3p+5=0
36+5=-3p
41÷-3=p
p= -13.67
first root alpha= -3
so second root = bita
given equation=
4x²+41/3x+5=0 (including value of p)
comparing with ax²+bx+c=o
a=4,b=41/3,c=5
sum of roots=
rithikareddy10:
ok ty sis
p = -41/3
we can find another root also
compare given equation with ax^2 +bx +c =0,
a= 4, b= -p, c= 5
let the second root = beta, one root = alpa = -3 given
product of the roots= c/a
beta * (-3) = 5/4
beta = 5/[4*(-3)= -5/12
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