Question

if one root of the quadratic equation 6x^-x-k=0 is 2/3 then find the value of k
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Answer 1

Answer:

Step-by-step explanation:

GIven : One root of the quadratic polynomial is 2/3.

To find : value of k

Solution : when root is applied inthe p(x) it will become 0 ie,

p(2/3)=0

6×(2/3)^2 -2/3 -k =0

6×4/9-2/3-k=0

Since 6 and 9 have common factor3 so we can divide it then we get,

2×4/3-2/3-k=0

8/3-2/3-k=0

6/3-k=0

2-k=0

k=2

Hence the solution