Question

If one root of the quadratic equation ax^2 + bx + 6a = 0 is 3. Then, the value of b/a is :

Answer 1

Step-by-step explanation:$\huge\mathcal{\fcolorbox{aqua}{azure}{\red{♡Answer★}}}$

Given equation is

ax

2

−bx+a=0...(i)

and one root is 6

Let α and β are the roots of the equation and α=6

From the equation

+β=

a

b

⇒6+β=

a

b

...(ii)

and αβ=

a

a

=1⇒

α

1

=

6

1

By putting β=

6

1

in Eq(ii), we get

6+

6

1

=

a

b

=

6

37