Question

If one root of the quadratic equation is 3-2√5 then write another root of the equation

Answer 1

X= 3-2√5

X-3= -2√5
squaring both sides

X^2-6x+9= 20

X^2-6X+9-20=0

X^2-6X-11=0

so Quadratic equation is
${x}^{2} - 6x - 11$=0

other root is 3+2√5

Mark it B

Answer 2

Step-by-step explanation:

X= 3-2√5

X-3= -2√5

squaring both sides

X^2-6x+9= 20

X^2-6X+9-20=0

X^2-6X-11=0

so Quadratic equation is

{x}^{2} - 6x - 11x

2

−6x−11 =0

other root is 3+2√5

Mark it B