Question

if one root of the quadratic equation kx square minus 3 x minus 1 is equals to zero is 1.2 then find the value of k

Answer 1

Kx^2-3x-1=0

one root is 1.2

Then put value of x=1.2

K(1.2)^2-3(1.2)-1=0

1.44K-3.6-1=0

1.44K = 4.6

K=4.6/1.44

K=3.1

Hope it helps

:)