Question

If one root of the quadratic equation kx2-14x+8=0 is 6 times the other, then find the value of k.

Answer 1

Answer:

Step-by-step explanation:

We substitute X=2

k(2)^2 - 14(2) +8= 0

4k-28+8=0

4k-20=0

4k=20

k=5

Answer 2

Answer:

Put K =2

Step-by-step explanation:

K(2)²-14(2)+8=0

4K-28+8=0

4K-20=0

4K=20

K=5