If one root of the quadratic equation kx²-14x+8=o is six times the other find the value of k
Answers
Answered by
2
Answer:
α + β = -b/a
α + 6α = 7α = 14/k
α = 2/k ....................(1)
α × β = c/a
α × 6α = 8/k
substituting (1)
2/k × 12/k = 8/k
24/k² = 8/k → 24/k = 8
k = 3
hope its helpful..............
Similar questions