Question

if one root of the quadratic equation
$6 {x}^{2} - x - k = 0$
is
$\frac{2}{3}$
then find the value of K

Answer 1

6x^2-x-k=0
x=2/3
6×(2/3)^2-2/3=k
6×4/9-2/3=k
8/3-2/3=k
8-2÷3=k
6÷3=k
k=2