if one root of the quadratic equation x^ - 11x + k = 0 is 9 find the value of k.
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9-11×9+k=0
-90+k=0
k=90
-90+k=0
k=90
Answered by
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given,
one root of the equation=9
x²-11x+k=0
9²-11(9)+k=0
81-99+k=0
18+k=0
k=-18
one root of the equation=9
x²-11x+k=0
9²-11(9)+k=0
81-99+k=0
18+k=0
k=-18
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