If one root of the quadratic equation x2-7x+k=0 is 4 then find the value of k
Answers
Answered by
6
Answer:
the value of k is 12
Step-by-step explanation:
putting the value of root of equation in equation it become zero .
x²-7x+k=0
4²-7×4=-k
16-28=-k
-k=-12
k=12
Answered by
1
Well here is the shortest method,
Let other root be x
=> 7 = 4+x => x=3
k = 4 x 3 = 12
Let other root be x
=> 7 = 4+x => x=3
k = 4 x 3 = 12
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