Question

If one root of the quadratic equations 2x_{2} + kx- 6x=0 is 2 , Find the value of k. Also Find the other root.​

Answer 1

Step-by-step explanation:

Since x=2 is a root of the equation

2x

2

+kx−6=0

2k+2=0

k=−1

Putting k =-1 in the given equation, we get,

2x

2

−x−6=0

(x−2)(2x+3)=0

x=2,−

2

3

Hence, the other root is −

2

3

.

Hope it's helpful to you

Answer 2

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If one root of the quadratic equations 2x_{2} + kx- 6x=0 is 2 , Find the value of k. Also Find the other root.

Solution :-Since x = 2 is a root of the equation 2x ^ {2} + kx- 6x = 0 .

∴ 2 × 2 + 2k - 6x = 0

⇒8 + 2k - 6 = 0

⇒ 2k + 2 = 0

⇒ k = -1

Putting k = -1 in the equation 2x^{2} + kx- 6x = 0 , we get

2x^{2} + kx- 6x = 0

⇢2x^{2} - 4x + 3x - 6 = 0

⇢ 2x ( x -2 ) + 3(x-2) = 0

⇢(x-2) (2x + 3) = 0

⇢ x - 2 = 0, 2x + 3 = 0

⇢ x = 2 , x = -3/2

Hence, the other root is -3/2.

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Note :- Mate , Your Question have little mistakes.Please check it.

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