Question

if one root of the quadratic equations 2x2+KX-6=0 is 2 find the value of k?​

Answer 1

Given, p(x) = 2x² + kx -6

and p(2) = 0

=> p(2) = 2(2)² + k(2) - 6 = 0

=> 8 + 2k - 6 = 0

=> 2 + 2k = 0

=> k = -1

Now, dividing p(x) by ( x - 2 ), we get p(x) = (x-2)(2x+3)

Hence, other root is 2x+3 = 0 => x = (-3/2)

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