Question

If one root of the quadratic equations kx square-14x+8=0 is six time the other, find the value of k

Answer 1

Answer:

Step-by-step explanation:

To find k

Now let one root be x. Therefore other is 6x

Here, a=k,b=-14,c=8

Now sum of roots=-b/a

6a+a=-(-14)/k

7a=14/k

Therefore, k=14/7a

k=2/a...1)

Product of roots is c/a

a*6a=8/k

6a²=8/k

k=8/6a²

k=4/3a²...2)

Therefore,

2/a=4/3a2( from 1) and 2) ) note that a² is in denominator

Therefore, 6a²=4a

On solving,

a=4/6

a=2/3

Therefore, k=2/2/3

k=3

Please try and understand