Math, asked by aarushi3734, 10 months ago

if one root of thr quadratic equation 2x2+2×+k=0 is-1/3 then find the value of k​

Answers

Answered by rudra09
15

Step-by-step explanation:

refer to te attachment........

Attachments:
Answered by pinquancaro
23

The value of k is \frac{4}{9}.

Step-by-step explanation:

Given : If one root of the quadratic equation 2x^2+2x+k=0 is -\frac{1}{3}.

To find : The value of k​ ?

Solution :

If  -\frac{1}{3} is the root of quadratic equation then it satisfy the equation.

So, put x=-\frac{1}{3} in the quadratic equation

2(-\frac{1}{3})^2+2(-\frac{1}{3})+k=0

\frac{2}{9}-\frac{2}{3}+k=0

\frac{2-6}{9}+k=0

\frac{-4}{9}+k=0

k=\frac{4}{9}

Therefore, the value of k is \frac{4}{9}.

#Learn more

If x=3 is one root of thr quadratic equation x^2-2x-6=0 then find the value of k.

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