Question

If one root of x^2-5x+(6+k)=0 is 0 find the value of k

Answer 1

$\bold{\red{ANSWER}}$

$\rm{\blue{-6}}$

$\rm{\pink{GIVEN\:QUESTION\:IS}}$

$\rm{x^2-5x+\left(6+k\right)=0}$

$\rm{\mathbb{EXPLANATION}}$

$\rm{The\:Given\:Equation\:Has\:Two\:Roots\:In\:Which}$

$\rm{one\:Of\:Them\:is\:0\:let\:The\:Other\:Root\:Be\:\alpha}$

$\therefore{\rm{x=0}}$

$\rm{\boxed{put\:the\:value\:of\:x\:in\:given\:equation\:we\:have}}$

$\rm{\left(0\right)^{2}-5\left(0\right)+\left(6+k\right)=0}$

$\rm{6+k=0}$

$\rm{k=-6}$

${\therefore\:k=-6}$

Answer 2

Answer:

Step-by-step explanation:

\rm{\left(0\right)^{2}-5\left(0\right)+\left(6+k\right)=0}

\rm{6+k=0}

\rm{k=-6}

{\therefore\:k=-6}