If one root of x^2+kx+6=0 is 1 then the value of k is
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Question
If one root of x^2+kx+6=0 is 1 then the value of k is
Answer
-7
Step-by-step explanation
p(x) = x² + k × x + 6
0 = (1)² + k + 6
0 = 1 + k + 6
0 = 7 + k
k = -7
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