Question

If one root of
x²+px+3=0 is 1 then



a) p = –1
b) p = 3
c) p = – 4
d) p = 4
please answer fast​

Answer 1

Answer:

$x {}^{2} + px + 3 = 0 \\ substituting \: the \: value \: of \: x \: as \: 1 \\ \\ {1}^{2} + p(1) + 3 = 0 \\ 1 + p + 3 = 0 \\ 4 + p = 0 \\ p = - 4$

Therefore,the value of p is -4

c) p = -4

Step-by-step explanation:

Hope it helps you

Mark as brainliest (✷‿✷)