Question

if one root of x2+px+3=0 is 1 then the value of p is

Answer 1

Answer:

p = 4

Step-by-step explanation:

If one root is 1

i. e. x = 1

p(x) = x²+px+3=0

Then substituting x = 1

p(1) = (1)²+p(1)+3

= 1+p+3

= 4+p

-p = 4

therefore, p = -4

IF SATISFIED,

MARK AS BRAINLIEST