Math, asked by tssvas66, 7 months ago

if one root of x2+px+3=0 then the value of p is

Answers

Answered by biju71
1

Answer:

x^2+px+3=0

D=b^2-4ac

a=1

b=p

c=3

D=p^2-4×1×3

0=p^2-12

p^2=12

p=√12

p=2√3

value of p is 2√3

Answered by Gautam308
1
He has given the correct answer
Mark him brainliest
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