if one root of x2+px+3=0 then the value of p is
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Answer:
x^2+px+3=0
D=b^2-4ac
a=1
b=p
c=3
D=p^2-4×1×3
0=p^2-12
p^2=12
p=√12
p=2√3
value of p is 2√3
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