Question

if one roots of x2 + px -7 = 0 is 7 then value of p is answer

Answer 1

Answer:

Let root of the given equation x

2 +px+q=0 are α and α 2

Then, we have α⋅α 2 =α 3 =q and α+α 2=−p

On cubing both sides, we get

α 3+(α 2 ) 3+3α.α 2(α+α 2 )=−p 3

⇒q+q 2+3q(−p)=−p 3

⇒p 3 +q 2+q(1−3p)=0

Answer 2

value of p is 8...

Step-by-step explanation:

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