Question

If one sees the bottom of a tree at a 45degree angle of descent from the top of a 30m high tower, what is the distance between the tree and the tower?

Answer 1

the height of the tower =30m

the angle of decent from the top of the tower to bottom of the tree = 45 degrees

by applying

$\tan(45)$

tan 45=ab/bc

tan45=ab/30

1=ab/30

by cross multiplication

ab =30m

.

. . the distance between the tower and the tree is 30 m