Question

if one side of a square is increased by 2 metre and its adjacent side is reduced by to meet a rectangle is formed whose perimeter is 48 find the side of the original square

Answer 1

12 is the original side

Answer 2

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HERE'S THE ANSWER..

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♠️ Let us assume a square of side ( x )

⏺️ Now according to question one side is increased by 2 meter and adjacent side is reduced is reduced by 2 meter

▶️ Side is increased by 2 meter

✔️ Length ( L ) = x + 2

▶️ Another side is decreased by 2 meter

✔️ Breadth ( B ) = x - 2

♠️ It formed a rectangle of perimeter 48 meter

⏺️ So perimeter of rectangle is

✔️2 ( length + breadth )

=> Perimeter = 2 ( L + B )

=> 48 = 2 [ ( x + 2 ) + ( x - 2 ) ]

=> 48 = 2 [ x - 2 + x - 2 ]

=> 48 = 2 [ x + x ]

=> 2 [ 2 x ] = 48

=> 4 x = 48

=> $\boxed{ x \:= \: 12 \: meter}$

♠️ The side of original square was 12 meter

HOPE HELPED..

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