Question

If one side of a square is increased by 2 metres and other side is reduced by 2 metres, a rectangle is formed
whose perimeter is 48. Find the side of the original square,​

Answer 1

Answer: let side of square

= x

According to question,

one side = (x + 2)

Other side = (x - 2)

perimeter of this square will be

= perimeter of Rectangle

(x+2) + (x-2) = 48

2x = 48 => x = 24

Side of the original square = 24m

Answer 2

Solution:

Let the side of the original square be 'x'.

One side when increased by 2m=(x+2)m

Other side when reduced by 2m=(x-2)m

.·.Perimeter = 2(l+b)

=> 48= 2[(x+2)+(x-2)]

=> 48= 2(x+2+x-2)

=> 48= 2x+4+2x-4

=> 48= 2x+2x

=> 48= 4x

=> 48/4= x

=> x= 12m

.·. The side of the original square is 12m.