If one side of a square is increased by 2 metres and the other side is reduced by 2 metres, a rectangle i
formed whose perimeter is 48 m. Find the side of the original square.
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let side of square be x
length of rectangle=x+2
breadth of rectangle=x-2
A/Q
2[(x+2)+(x-2)]=48
2[2x]=48
4x=48
x=48/4
x=12
So,side of square=12 cm
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