if one side of a square is increased by 3m and the other side is reduced by 2m , the rectangle formed whose area is 4 m square more than the area of the original square. find the side of the original square
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13
Answer:
Let x be the side of the square.
Area of the square= x^2
Area of the rectangle
= length * breadth
= (x+3)(x-2)
Given that area if the rectangle is 4 m.sq more than area of the square
(x+3)(x-2)= (x^2) + 4
(x^2) + 3x - 2x -6 = (x^2) + 4
(x^2) + x -6 = (x^2) + 4
x -6 = 4
x= 4+6
x=10.
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Answered by
16
if one side of a square is increased by 3m and the other side is reduced by 2m , the rectangle formed whose area is 4 m square more than the area of the original square. find the side of the original square.
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