if one side of a square is increased by 5 metre and the other side is reduced by 5 metre a rectangle is formed whose perimeter is 30 metre find the side of original square
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let the sides of square be x
when increased by 5m:- (x+5)
other side decreased by 5m :-(x-5)
perimeter=30m
A.T.Q.
2(l+b)=30
2(x+5+x-5)=30
2x^2=30
x^2=15
3.87m
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Answer:
If one side of a square is increased by 5metres and the other side is reduced by 5 metres , a rectangle is formed whose perimeter is 30 m . Find the side of the original square .
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