If one side of a trapezium is 5 more than other distance them is 20cm and area of trapezium is 500cm square.
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I don't know....I don't know I DPN tkjow indpn tkjkpw I don't know
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area of trapezium is 1/2(a+b)h
so. according to quetion
let one side be x so other will be x+5
and if we put this sides in the formula we can get solution of these type:
area of trap.... is = 1\2(a+b)h
500=1/2(x+5+x)20
500= (2x+5)10
500/10= 2x+5
50=2x+5
50/2=x+5
25 =x+5
25-5 =x
20 = x
if we get x so we also get another side that is
x+5
x=20
x+5=20+5=25
we find the sides .if you put in the formula the value of x you can find it
so. according to quetion
let one side be x so other will be x+5
and if we put this sides in the formula we can get solution of these type:
area of trap.... is = 1\2(a+b)h
500=1/2(x+5+x)20
500= (2x+5)10
500/10= 2x+5
50=2x+5
50/2=x+5
25 =x+5
25-5 =x
20 = x
if we get x so we also get another side that is
x+5
x=20
x+5=20+5=25
we find the sides .if you put in the formula the value of x you can find it
Thedoubtclearer:
what you want to ask sides or area
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