If one side of a triangle is 3 X + 4 and other side is 4 x + 5 and the last side is X + 11 then what is the value of x
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Answer:
3 sides of a triangle = 180°
3x+4+4x+5+x+11=180°
8x+20=180°
8x=180-20
8x=160
x=160/8
x=20
3x+4=
3x20+4=64°
4x+5=
4x20+5=85°
x+11=
20+11=31°
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