Question

if one side of square is increased by 3m and other side is reduced by 2m a rectangle is formed whose area is 4 m sq. more than the area of the original square
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Answer 1

Answer:

Let x be the side of the square.

Area of the square= x^2

Area of the rectangle

= length * breadth

= (x+3)(x-2)

Given that area if the rectangle is 4 m.sq more than area of the square

(x+3)(x-2)= (x^2) + 4

(x^2) + 3x - 2x -6 = (x^2) + 4

(x^2) + x -6 = (x^2) + 4

x -6 = 4

x= 4+6

x=10.

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