Question

if one side of square is increased
by
5 meters and the other sides
is decreased by 5 m, a
rectangle is
formed whose
perimeter is 30 m ,
Find the side
original square​

Answer 1

Gɪᴠᴇɴ :-

If one side of square is increased by 5 meters and the other sides is decreased by 5 m, a rectangle is formed whose perimeter is 30m

Tᴏ ғɪɴᴅ :-

• Side of Square

sᴏʟᴜᴛɪᴏɴ :-

Let side of square be x m

then,

✞ According to 1st Condition :-

RECTANGLE

• Length(l) = (x + 5)
• Breadth (b) = (x - 5)
• Perimeter = 30m

✞ According to 2nd Condition :-

We know that,

• Perimeter of Rectangle = 2(l + b)

➭ 2(l + b) = 30

➭ ( l + b) = 30/2

➭ (l + b) = 15. ---(1)

Put the above values of l and b in (1), we get,

➭ (x + 5) + (x - 5) = 15

➭ x + x = 15

➭ 2x = 15

➭ x = 15/2

➭ x = 7.5 m

Hence,

• Side of Square = x = 7.5m

Answer 2

Answer:

let the 2 sides be x-5, x+5

perimeter of rectangle 2(l+b)

2(x-5) +(x+5) =30

(x-5) +(x+5) =30/2

x+x = 15

2x=15

x= 15/2

x= 7.5 m