Question

if one side of triangle is equal to the sum of square of other two sides then prove that the triangle is right angle​

Answer 1

Answer:

In a triangle, if square of one side is equal to sum of square of other two sides, then prove that the angle opposite to the side is right angle. Thus ΔABC≅ΔPQR=∠B=90o.

Step-by-step explanation:

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Answer 2

Answer:

Theorem 6.9 : In a triangle, if square of one side is equal to the sum of the squares of the other two sides, then the angle opposite the first side is a right angle.

Step-by-step explanation:

HEY GUYS .............

Given : AC2 = AB2 + BC2

To prove : angle B = 90°

Proof : In triangle PQR

PR2 = PQ2 + QR2 ( Pythagoras theorem ) (1)

AC2 = AB2 + BC2 (2)

From (1) { Cons. AB = PQ, BC = QR}

PR2 = AB2 + BC2 (3)

From (2) and (3)

AC2 = PR2

AC = PR (4)

In triangle ABC And triangle PQR

AC = PR

AB = PQ

BC = RQ

Triangle ABC ~= PQR [ SSS]

CPCT Angle B = Q

Angle Q = 90°

Angle B = 90°

HENCE PROVED

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