if one solution of second degree equation x2-9x+k=0 is 5
a) what is the value of k?
b)what is the other solution?
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Step-by-step explanation:
x2-9x+k=0
if one solution is 5
p(5) = (5)^2-9×5+k
25-45+k =0
-20 +k = 0
k = 20
b) other solution
x2-9x+20=0
x^2-(4+5)x+20= 0
x^2-4x-5x+20=0
x(x-4)-5(x-4)=0
(x-5)(x-4)=0
x-4=0
x = 4 is other solution
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