Question

if one solution of second degree equation x2-9x+k=0 is 5
a) what is the value of k?
b)what is the other solution?​

Answer 1

Step-by-step explanation:

x2-9x+k=0

if one solution is 5

p(5) = (5)^2-9×5+k

25-45+k =0

-20 +k = 0

k = 20

b) other solution

x2-9x+20=0

x^2-(4+5)x+20= 0

x^2-4x-5x+20=0

x(x-4)-5(x-4)=0

(x-5)(x-4)=0

x-4=0

x = 4 is other solution