Question

If one square with a side length of 6 inches is inside another square with a side length of 9 inches, what method should be used to find the difference between their areas?

Answer 1

Solution

Given :-

• Side of first Square = 6 inches
• Side of second Square = 9 inches

Find :-

• Difference between firt & second Square

Explanation

Using Formula

$\star\tt{\red{\:Area_{Square}\:=\:(Side)^2}}$

Now, Calculate area of first Square

==> Area of first Square = (6)²

==> Area of first Square = 6 × 6

==> Area of first Square = 36 inches²

Now, Calculate area of second Square

==> area of second Square = (9)²

==> area of second Square = 9 × 9

==> area of second Square = 81 inches²

Now, Calculate difference between first & second Square area

==> Difference area = Second square area - First Square area

==> Difference area = 81 - 36

==> Difference area = 45 inches²

Hence

• Difference area will be = 45 inches²

__________________

Answer 2

Answer:

Given:-

• Side of first square is 6 inches.
• Side of second square is 9 inches.

To Find:-

• The difference between their areas?

Solution:-

Formula to find area of square:-

$\dag \: \boxed {\underline { \rm{ \pink{ side \times side}}}}$

Area of first square:-

• Area = (6)²
• Area = 6×6
• Area = 36 inches²

Area of second square:-

• Area = (9)²
• Area = 9×9
• Area = 81 inches²

Now, difference between their areas:-

$\dag\: \boxed {\underline { \rm{ \blue{ area \: \: of \: second \: square - area \: of \: first \: square}}}}$

• Difference = 81 - 36
• Difference = 45 inches²

Hence, the difference between their areas is 45 inches².