Question

If one values of x of equation 2x^2-6x+k=0 be 1/2 (a+5i) find values of a and k

Answer 1

A=
$\frac{3}{2}$
K=
$\frac{109}{8}$

Answer 2

Step-by-step explanation:

complex roots always occur in conjugate pair

2x2−6x+k=0

sum=3

product = 2k

one root is 2α+5i

other root is 2α−5i

sum=2α+5i+2α−5i=3

α=3

product = k = (23+5i)(23−5i)

=49−25i2=49+25=17 /2