Question

if one xero of the polynomial x^2 - 4x + 1 is 2+ root 3 ,find the other zero.With a brief explanation pls

Answer 1

Answer:

Let p( x ) = x² - 4x + 1 ,compare p( x ) with ax² + bx + c ,a = 1 , b = -4 , c = 1 one zero = 2 + √3 Let second zero = p sum of the zeroes = -b/ap + ( 2 + √3 ) = - ( - 4 )p = 4 - ( 2 + √3 )p = 2 - √3 orproduct of the zeroes = c/a ( 2 + √3 ) p = 1p = 1/ ( 2 + √3 )p = ( 2 - √3 ) / [ ( 2 + √3 ) ( 2 - √3 ) ]= ( 2 - √3 ) / [ 2² - ( √3 )² ]= ( 2 - √3 ) / ( 4 - 3 )= 2 - √3 Therefore ,required second zero of p( x ) p = 2 - √3 I hope this helps you.

Step-by-step explanation:

Answer 2

Step-by-step explanation:

hus, for k = -21, 3 is a zero of the polynomial.