Question

If one zero 7x2-(p+2)x-8 Is negative of other than find the value of p

Answer 1

Answer:

p=-2

Step-by-step explanation:

Let the roots be

$\alpha$

and other root be

$\beta$

Since one root is negative of the other, their sum is zero.

So,

$\alpha + \beta = 0$

We know that

$\alpha + \beta = \frac{ - b}{a} \\ 0 = \frac{p + 2}{7} \\ p + 2 = 0 \\ p = - 2$

Hence, p=-2 is the required answer.

Thank you