Question

If one zero is seven times the other, then find the zeroes and the value of k of p(x)=3x^2-8x-2k-1

Answer 1

yr answer☝...............

Answer 2

Hi: friend here we let's zeroes is A
then according the question
first zeroes =A
and second zeroes = seven time ×first zeroes
therefore :A+7A=-(-8)/3
8A=8/3
A=1/3 ___________________(1)
and : A×7A = -2K-1/3
From eqn.(1)
1/3×7×1/3= -2k-1/3
7= -18k--3
7+3= -18k
10=-18k
k=-5/9