Question

If one zero is the negative of the other, 4x^2
-8kx-9, find k.

Answer 1

Step-by-step explanation:

let the two roots be n and -n as it is given that one zero is the negative of the other. So substitute n and -n in the equation

$4 {x}^{2} - 8kx - 9$

So

$4 {n}^{2} - 8kn - 9 = 4 {( - n)}^{2} - 8k( - n)$

$- 9 = > - 8kn = 8kn = > 16kn = 0$

$= > k = 0$

Hope it helps you.

Answer 2

Step-by-step explanation:

Answer :-

→ k = 0 .

Step-by-step explanation :-

It is given that,

→ One zeros of the given polynomial is negative of the other .

Let one zero of the given polynomial be x .

Then, the other zero is -x .

•°• Sum of zeros = x + ( - x ) = 0 .

But, Sum of zeros = -( coefficient of x )/( coefficient of x² ) = - ( -8k )/4 .

==> 2k = 0 .

==> k = 0/2 .

•°• k = 0 . .............

Hence, it is solved.