if one zero of 2 x square - 3 x + K is reciprocal to the other then find the value of k
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Answered by
6
Given Equation is 2x^2 - 3x + k.
Let the zeroes be 1 and 1/a.
Given that the roots are reciprocal.
Therefore the product of the roots = a * 1/a = constant term/coefficient of x^2
1 = k/2
k = 2.
therefore the value of k = 2.
Hope this helps!
Let the zeroes be 1 and 1/a.
Given that the roots are reciprocal.
Therefore the product of the roots = a * 1/a = constant term/coefficient of x^2
1 = k/2
k = 2.
therefore the value of k = 2.
Hope this helps!
HappiestWriter012:
bro I have one doubt
Answered by
4
Let one root be v then another root will be 1/v
Given quadratic equation = 2x²-3x+k = 0
Comparing it with general quadratic equation, we get a = 2 , b = -3 , c = k
We know that Product of roots = v × 1/v = k/2
=> 1 = k/2
=> k = 2 .
Given quadratic equation = 2x²-3x+k = 0
Comparing it with general quadratic equation, we get a = 2 , b = -3 , c = k
We know that Product of roots = v × 1/v = k/2
=> 1 = k/2
=> k = 2 .
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