If one zero of 2x^2=3x+k is reciprocal to each other. Then find the value of k.
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2x²= 3x+k
= 2x²-3x-k = 0
Product of zeroes = c/a
a×1/a = -k/2
1 = -k/2
K = -2
= 2x²-3x-k = 0
Product of zeroes = c/a
a×1/a = -k/2
1 = -k/2
K = -2
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