If one zero of 2x^2x-3x+k is reciprocal of other,find k=?
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3
Answer:
Given a quadratic equation:2x² – 3x + k
Also given one of the zeros of 2x² – 3x + k is reciprocal to the other,
We need to find the value of k.
Solution
Let us assume that one zeros of the given quadratic equationbe(2x² – 3x + k) be α
Hence the other zero is reciprocal of the zero. So the other zero is 1/α
As per the given equation
a = 2 b = -3 c = k
So, α x 1/α = c/a
1 = k/2
k = 2
The value of k is 2
Answered by
0
Answer:
2X²-3X+k
suppose. 2X²-3X+k = 0
= 2X²+k = 3X
= k = 3X-2X²
= K=X
then K=X.
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