if one zero of 2x-3x+k is reciprocal to other then find the value of k
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Let one zero be β and another zero is 1/β.
Given polynomial,
2x² - 3x + k
Comparing with ax² + bx + c, we get
a = 2 , b = -3 , c = k
Product of zeroes = c/a
(β)(1/β) = c/a
1 = k/2
k = 1 × 2
k = 2
Given polynomial,
2x² - 3x + k
Comparing with ax² + bx + c, we get
a = 2 , b = -3 , c = k
Product of zeroes = c/a
(β)(1/β) = c/a
1 = k/2
k = 1 × 2
k = 2
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