Question

If one zero of 2x square - (3k+1)x - 9 is negative of the other,find the value of k.

Answer 1

let one zero is
$\alpha$ and other zero is $- \alpha.$
$sum of zeros \alpha - \alpha = \frac{ - b}{a} = \frac{3k + 1}{2} \\ 0 = \frac{3k + 1}{2} \\ 3k + 1 = 0 \\ 3k = - 1 \\ k = \frac{ - 1}{3}$