Question

If one zero of 2x²-3x+k is 2, then the value of k is *

Answer 1

Answer:-2

Step-by-step explanation:

$p(x) = 2 {x}^{2} - 3x + k \\ \\ \\ p(2) = 2× {(2)}^{2} - 3 \times 2 + k \\ = > 0 = 2 \times 4 - 6 + k \\ = > 0 = 8 - 6 + k \\ = > k +2 = 0 \\ = > k = -2$

Answer 2

Answer:

p(x) = 2x²-3x+k = 0

one zero of 2x²-3x+k is 2

p(2) = 2(2)^2-3(2)+k = 0

= 8 -6 +k = 0

= 2 + k = 0

= k = -2

hope it helps you