if one zero of 3 x square - 4 - 3K X + 5 is negative of the other then find the value of k
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Given expression, 3x^2 -(4-3k)x +5
Let first zeros be the r then second zeros will be -r
applying the sum of zeros, r+(-r)=-(b)/a
and we have, a=3, b=-(4-3k) and c=5
Therefore, r+(-r)=-(-(4-3k)/3
(4-3k)/3=0
4-3k=0
3k=4
k=4/3
Step-by-step explanation:
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