Question

if one zero of 3x^2-8x-(2k+1) is seven times the other, find the value of k

Answer 1

Hey friend here is your answer

It is given that one zero is 7 times the other so, let us take one zero as X so other zero becomes 7X

Given polynomial is 3x^2-8x-(2k+1)

Using relationship between zeroes and coefficient

X+7X= 8/3

8X=8/3


X=1/3. 7X=7/3

Putting value of X in eq

3*(1/3)2-8*1/3-(2k+1)

3*1/9-8/3-(2k+1)

1/3-8/3-(2k+1)=0

-7/3-2K-1=0
-2k=1+7/3

-2k=10/3

K=10/3 *1/2

K=-5/3


Hope it helps you ✌✌